Veja como resolver esse problema:

1. Escreva a equação química equilibrada

The reaction between zinc sulfide (ZnS) and hydrochloric acid (HCl) produces zinc chloride (ZnCl₂) and hydrogen sulfide gas (H₂S):

ZnS(s) + 2HCl(aq) → ZnCl₂(aq) + H₂S(g)

2. Convert Grams of ZnS to Moles

* Find the molar mass of ZnS:(65.38 g/mol Zn) + (32.06 g/mol S) =97.44 g/mol
* Divide the mass of ZnS by its molar mass:56.5 g / 97.44 g/mol =0.580 mol ZnS

3. Use the Mole Ratio to Find Moles of HCl

* The balanced equation shows a 1:2 mole ratio between ZnS and HCl.
* Multiply the moles of ZnS by 2 to find the moles of HCl needed:0.580 mol ZnS * 2 =1.16 mol HCl

4. Assume a Concentration for HCl

* You need to know the concentration of the HCl solution to calculate the volume. Let's assume we have a 1.0 M HCl solution (meaning 1 mole of HCl per liter of solution).

5. Calculate the Volume of HCl

* Use the molarity and moles of HCl to find the volume:
Volume =Moles / Molarity =1.16 mol / 1.0 mol/L =1.16 L
* Convert liters to milliliters:1.16 L * 1000 mL/L =1160 mL

Therefore, you would need approximately 1160 milliliters of 1.0 M hydrochloric acid to react with 56.5 grams of zinc sulfide.

Nota importante: This calculation assumes complete reaction. Na realidade, fatores como condições de reação e pureza dos reagentes podem afetar o volume real necessário.