Veja como resolver esse problema:

Entendendo o conceito

* Molaridade: Molarity (M) is a unit of concentration that represents the number of moles of solute per liter of solution.
* Barium Chloride (BaCl₂) : Barium chloride is an ionic compound that dissociates in water to form barium ions (Ba²⁺) and chloride ions (Cl⁻) in a 1:2 ratio.

Etapas

1. Dissociation Equation:
BaCl₂(aq) → Ba²⁺(aq) + 2Cl⁻(aq)

2. Moles of Barium Chloride:
* We have 100 ml of a 500 M barium chloride solution.
* Convert ml to liters:100 ml * (1 L / 1000 ml) =0.1 L
* Moles of BaCl₂ =Molarity * Volume (in liters) =500 M * 0.1 L =50 moles

3. Moles of Chloride Ions:
* From the dissociation equation, 1 mole of BaCl₂ produces 2 moles of Cl⁻.
* Moles of Cl⁻ =50 moles BaCl₂ * (2 moles Cl⁻ / 1 mole BaCl₂) =100 moles Cl⁻

4. Molarity of Chloride Ions:
* Molarity of Cl⁻ =Moles of Cl⁻ / Volume of solution (in liters) =100 moles / 0.1 L =1000 M

Therefore, the molarity of chloride ion in 100 ml of a 500 M barium chloride solution is 1000 M.